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-3x^2+35x-32=0
a = -3; b = 35; c = -32;
Δ = b2-4ac
Δ = 352-4·(-3)·(-32)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{841}=29$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-29}{2*-3}=\frac{-64}{-6} =10+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+29}{2*-3}=\frac{-6}{-6} =1 $
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